Math Component

Question: A cannonball is shot upward from the upper deck of a fort with an initial velocity of 192 feet per second.  The deck is 32 feet above the ground. 
Initial velocity equation: (speed (ft/sec))cos(launch angle)
h = -16t²+v₀t+h₀

h= -16t²+192t+32

Question 1: How high does the cannonball go? 608 feet
Question 2: How long is the cannonball in the air? 12.16 seconds


To solve put the equation in your calculator and find look for the highest number in your table.
Then use quadratic formula to find the x intercept.